Allen, New York
Town in New York, United States / From Wikipedia, the free encyclopedia
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Allen is a town in Allegany County, New York, United States. The population was 493 at the 2020 census.[2] The town is named after Ethan Allen.
This article includes a list of general references, but it lacks sufficient corresponding inline citations. (June 2014) |
Quick Facts Country, State ...
Allen | |
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Coordinates: 42°23′09″N 78°00′55″W | |
Country | United States |
State | New York |
County | Allegany County |
Incorporated | 1823 |
Government | |
• Town Supervisor | Diane Harris
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Area | |
• Total | 36.58 sq mi (94.74 km2) |
• Land | 36.38 sq mi (94.22 km2) |
• Water | 0.20 sq mi (0.53 km2) |
Elevation | 2,021 ft (616 m) |
Population | |
• Total | 493 |
• Estimate (2021)[2] | 488 |
• Density | 12.15/sq mi (4.69/km2) |
Time zone | UTC-5 (EST) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 14711, 14709, 14735 |
Area code | 585 |
FIPS code | 36-003-01319 |
Website | Town website |
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The Town of Allen is in the north-central part of Allegany County.