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The 2019 Jacksonville mayoral election was held on March 19, 2019, to elect the mayor of Jacksonville. Incumbent mayor Lenny Curry, a Republican, won a majority of votes to win a second term in office.[2] No Democratic candidate qualified for the mayoral election.[3]
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Turnout | 24%[1] | ||||||||||||||||||||||||||||||||||
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Results by precinct Curry: 30–40% 40–50% 50–60% 60–70% 70–80% 80–90% Brosche: 30–40% 40–50% | |||||||||||||||||||||||||||||||||||
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While Democratic candidates did declare their candidacy, no Democratic candidates qualified for the mayoral election in 2019.
Democrats did not field a candidate for Mayor of Jacksonville in the 2019 election. Curry faced Anna Lopez Brosche, described by The Florida Times-Union as a moderate Republican. Brosche's campaign received support from some Democratic politicians, including city councilman Garrett Dennis and former Duval County Democratic Party chair Lisa King.[3]
Party | Candidate | Votes | % | |
---|---|---|---|---|
Republican | Lenny Curry (incumbent) | 84,545 | 57.62 | |
Republican | Anna Lopez Brosche | 35,404 | 24.13 | |
Independent | Omega Allen | 15,453 | 10.53 | |
Republican | Jim Hill | 11,056 | 7.54 | |
write-in | Michael Romero | 263 | 0.18 | |
Total votes | 146,721 | 100.00 | ||
Republican hold |
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