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The 1990 Maryland gubernatorial election was held on November 6, 1990. Incumbent Democrat William Donald Schaefer defeated Republican nominee William S. Shepard handily (59.76% to 40.23%).
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| Turnout | 54.85%[1] | |||||||||||||||||||
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County results Schaefer: 50-60% 60-70% 70-80% Shepard: 50-60% 60-70% | ||||||||||||||||||||
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As of 2023[update], this was the last occasion that the following counties have voted Democratic in a gubernatorial election: Cecil, Calvert, Harford, St. Mary's, and Worcester.[original research?]
Primary elections were held on September 11, 1990.[2]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | William Donald Schaefer (incumbent) | 358,534 | 78.05 | |
| Democratic | Frederick M. Grisser Jr. | 100,816 | 21.95 | |
| Total votes | 459,350 | 100.00 | ||
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | William S. Shepard | 66,966 | 52.72 | |
| Republican | Ross Zimmerman Pierpont | 60,065 | 47.28 | |
| Total votes | 127,031 | 100.00 | ||
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic | William Donald Schaefer (incumbent) | 664,015 | 59.76% | ||
| Republican | William S. Shepard | 446,980 | 40.23% | ||
| Majority | 217,035 | ||||
| Turnout | 1,111,088 | ||||
| Democratic hold | Swing | ||||
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