1910 Belgian general election

Partial general elections were held in Belgium on 22 May 1910.^[1] The result was a victory for the Catholic Party, which won 49 of the 87 seats up for election in the Chamber of Representatives.^[2]

1910 Belgian general election

← 1908 22 May 1910 1912 →
87 of the 166 seats in the Chamber of Representatives
First party Second party   Leader Frans Schollaert Party Catholic Liberal Seats won 49 15 Popular vote 676,849 236,467 Percentage 53.11% 18.55%   Third party Fourth party   Leader Georges Maes N/A Party Labour Liberal–Socialist Seats won 6 17 Popular vote 85,326 243,063 Percentage 6.69% 19.07%
Government before election Schollaert Catholic Government after election Schollaert Catholic

Under the alternating system, elections were only held in five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders.

Results

Liberal Adolphe May defeated Catholic Emile de Lalieux de La Rocq in Nivelles and socialist Joseph Bologne defeated liberal Léopold Gillard in Namur. All other representatives were either re-elected, or succeeded by candidates of the same party. Notably, Camille Huysmans (socialist of Antwerp) was elected for the first time.

Party		Votes	%	Seats
				Won
	Catholic Party	676,849	53.11	49
	Liberal–Socialist kartels	243,063	19.07	17
	Liberal Party	236,467	18.55	15
	Belgian Labour Party	85,326	6.69	6
	Catholic dissidents	13,688	1.07	0
	Christene Volkspartij	11,494	0.90	0
	Democratic Party	872	0.07	0
	Socialist dissidents	99	0.01	0
	Independents	6,641	0.52	0
Total		1,274,499	100.00	87
Valid votes		1,274,499	97.53
Invalid/blank votes		32,258	2.47
Total votes		1,306,757	100.00
Source: Belgian Elections

References

1. Nohlen, Dieter; Stöver, Philip (31 May 2010). Elections in Europe: A data handbook. Nomos Verlagsgesellschaft. p. 289. ISBN 978-3-8329-5609-7.
2. Nohlen & Stöver, p308