1896 Belgian general election

Partial legislative elections were held in Belgium on 5 and 12 July 1896.^[1] Under the alternating system, elections were held in only five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders. Only 77 seats out of the 152 seats in the Chamber of Representatives were up for election. The Catholic Party retained their absolute majority.^[2]

1896 Belgian general election

← 1894 5 July 1896 1898 →
77 of the 152 seats in the Chamber of Representatives
First party Second party Third party   Leader Paul de Smet de Naeyer N/A Party Catholic Liberal Liberal–Socialist Seats won 72 1 4 Popular vote 492,541 193,563 49,614 Percentage 49.68% 19.52% 5.00%
Government before election de Smet de Naeyer I Catholic Government after election de Smet de Naeyer I Catholic

The Liberal Party, who lost two-thirds of their seats in the previous elections, saw their number of seats decrease further.

Results

Party		Votes	%	Seats
				Won
	Catholic Party	492,541	49.68	72
	Liberal Party	193,563	19.52	1
	Belgian Labour Party	150,260	15.16	0
	Liberal–Socialist kartels	49,614	5.00	4
	Other parties	105,394	10.63	0
Total		991,372	100.00	77
Source: Belgian Elections

References

1. Nohlen, Dieter; Stöver, Philip (31 May 2010). Elections in Europe: A data handbook. Nomos Verlagsgesellschaft. p. 289. ISBN 978-3-8329-5609-7.
2. Nohlen & Stöver, p307