1844 United States presidential election in Kentucky

Main article: 1844 United States presidential election

The 1844 United States presidential election in Kentucky took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for President and Vice President.

1844 United States presidential election in Kentucky

← 1840 November 1 - December 4, 1844 1848 →

Nominee Henry Clay James K. Polk Party Whig Democratic Home state Kentucky Tennessee Running mate Theodore Frelinghuysen George M. Dallas Electoral vote 12 0 Popular vote 61,249 51,988 Percentage 54.09% 45.91%

County Results Clay   50-60%   60-70%   70-80%   80-90% Polk   50-60%   60-70%   70-80%   80-90%

President before election John Tyler Independent Elected President James K. Polk Democratic

Kentucky voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won his home state by a margin of 8.18%.

With 54.09% of the popular vote, Clay's home state would be his third strongest victory after Rhode Island and Vermont.^[1]

Results

1844 United States presidential election in Kentucky[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Whig	Henry Clay of Kentucky	Theodore Frelinghuysen of New York	61,249	54.09%	12	100.00%
	Democratic	James K. Polk of Tennessee	George M. Dallas of Pennsylvania	51,988	45.91%	0	0.00%
Total				113,237	100.00%	12	100.00%

References

1. "1844 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
2. "1844 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved December 23, 2013.