1816 United States presidential election in Ohio

Main article: 1816 United States presidential election

The 1816 United States presidential election in Ohio took place between November 1 and December 4, 1816, as part of the 1816 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.

1816 United States presidential election in Ohio

← 1812 November 1 – December 4, 1816 1820 →

Nominee James Monroe Rufus King Party Democratic-Republican Federalist Home state Virginia New York Running mate Daniel D. Tompkins John E. Howard Electoral vote 8 0 Popular vote 3,326 593 Percentage 84.87% 15.13%

President before election James Madison Democratic-Republican Elected President James Monroe Democratic-Republican

Ohio elected Democratic-Republican candidate James Monroe over Federalist candidate Rufus King. Monroe won Ohio by a margin of 69.74%.

Results

1816 United States presidential election in Ohio[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	James Monroe	3,326	84.87%	8
	Federalist	Rufus King	593	15.13%	0
Totals			3,919	100.0%	8

See also

• United States presidential elections in Ohio

References

1. Ohio. Secretary of State. (1909). Ohio election statistics: the general election. Springfield, Ohio: The Springfield Publishing Company, State Printers. p. 3. OCLC 5470967. Retrieved December 8, 2019.