1804 United States presidential election in Kentucky
From Wikipedia, the free encyclopedia
From Wikipedia, the free encyclopedia
The 1804 United States presidential election in Kentucky took place between 2 November and 15 December 1804, as part of the 1804 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President. Kentucky had gained four electors compared to the previous election in 1800.[1]
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Kentucky cast eight electoral votes for the Democratic-Republican candidate and incumbent President Thomas Jefferson over the Federalist candidate Charles C. Pinckney. The electoral votes for Vice president were cast for Jefferson's running mate George Clinton from New York. The state was divided into two electoral districts with four electors each, whereupon each district's voters chose the electors.[2]
| 1804 United States presidential election in Kentucky[3] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | Thomas Jefferson (incumbent) | 5,080 | 100.0% | 8 | |
| Federalist | Charles C. Pinckney | 0 | 0.00% | 0 | |
| Totals | 5,080 | 100.0% | 8 | ||
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