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Celina, Ohio
City in Ohio, United States / From Wikipedia, the free encyclopedia
Celina (/səˈlaɪnə/ sə-LY-nə) is a city in and the county seat of Mercer County, Ohio, United States[6] about 58 miles (93 km) northwest of Dayton. The population was 10,935 at the 2020 census. Celina is situated on the northwestern shores of Grand Lake St. Marys.[7][8]
Quick Facts Country, State ...
Celina, Ohio | |
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![]() Downtown Celina | |
Nickname: C-Town | |
Motto: "One Of The 100 Best Small Towns!" | |
![]() Location in Mercer County and the state of Ohio. | |
Coordinates: 40°33′18″N 84°33′45″W | |
Country | United States |
State | Ohio |
County | Mercer |
Township | Center, Jefferson |
Government | |
• Mayor | Jeffrey Hazel[1] |
Area | |
• Total | 5.35 sq mi (13.87 km2) |
• Land | 5.03 sq mi (13.02 km2) |
• Water | 0.33 sq mi (0.84 km2) |
Elevation | 886 ft (270 m) |
Population (2020) | |
• Total | 10,935 |
• Estimate (2023)[4] | 10,885 |
• Density | 2,174.82/sq mi (839.71/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP codes | 45822, 45826 |
Area code | 419 |
FIPS code | 39-12868[5] |
GNIS feature ID | 2393778[3] |
Website | City of Celina, Ohio |
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