Jefferson Township, Switzerland County, Indiana
Township in Indiana, United States / From Wikipedia, the free encyclopedia
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Jefferson Township is one of six townships in Switzerland County, Indiana, United States. As of the 2020 census, its population was 3,203 and it contained 1,549 housing units.[1]
More information Census, Pop. ...
Census | Pop. | Note | %± |
---|---|---|---|
1890 | 3,491 | — | |
1900 | 3,350 | −4.0% | |
1910 | 2,713 | −19.0% | |
1920 | 2,516 | −7.3% | |
1930 | 2,401 | −4.6% | |
1940 | 2,441 | 1.7% | |
1950 | 2,542 | 4.1% | |
1960 | 2,532 | −0.4% | |
1970 | 2,365 | −6.6% | |
1980 | 2,487 | 5.2% | |
1990 | 2,657 | 6.8% | |
2000 | 3,111 | 17.1% | |
2010 | 3,167 | 1.8% | |
2020 | 3,203 | 1.1% | |
Source: US Decennial Census[2] |
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Quick Facts Country, State ...
Jefferson Township | |
---|---|
Coordinates: 38°47′47″N 85°03′08″W | |
Country | United States |
State | Indiana |
County | Switzerland |
Government | |
• Type | Indiana township |
Area | |
• Total | 37.2 sq mi (96 km2) |
• Land | 36.96 sq mi (95.7 km2) |
• Water | 0.24 sq mi (0.6 km2) 0.65% |
Elevation | 719 ft (219 m) |
Population (2020) | |
• Total | 3,203 |
• Density | 86/sq mi (33/km2) |
ZIP codes | 47011, 47020, 47043 |
GNIS feature ID | 453499 |
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