Jefferson Kūn (Ohio)
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Jefferson Kūn (Eng-gí: Jefferson County) sī Bí-kok Ohio chiu ê kūn (county), ū jîn-kháu 67964[1].
Chi̍t phiⁿ bûn-chiuⁿ su-iàu chìn-chi̍t-pō͘ ê khok-chhiong. Chhiáⁿ tàu-tīn lâi kái-siān chi̍t phiⁿ bûn-chiuⁿ ê phín-chit. |
Quick Facts , Ohio, Kiàn-li̍p ...
Jefferson County, Ohio | |
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Jefferson Kūn Jefferson County | |
Jefferson Kūn ê kéng-sek | |
Tī Bí-kok Ohio chiu ê ūi-tì | |
Kiàn-li̍p | 7 goe̍h 27 ji̍t, 1797 nî |
Kūn-hú | Steubenville |
Jîn-kháu | |
• Chóng-kè | 69,709 |
Bāng-chām |
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