Tanhc函數定義如下[1] Tanhc 2D plot Tanhc'(z) 2D Tanhc 積分圖 Tanhc integral 3D plot t a n h c ( z ) = tanh ( z ) z {\displaystyle tanhc(z)={\frac {\tanh \left(z\right)}{z}}} 復域虛部 I m ( tanh ( x + i y ) x + i y ) {\displaystyle {\it {Im}}\left({\frac {\tanh \left(x+iy\right)}{x+iy}}\right)} 復域實部 R e ( tanh ( x + i y ) x + i y ) {\displaystyle {\it {Re}}\left({\frac {\tanh \left(x+iy\right)}{x+iy}}\right)} 復域絕對值 | tanh ( x + i y ) x + i y | {\displaystyle \left|{\frac {\tanh \left(x+iy\right)}{x+iy}}\right|} 一階微商 1 − ( tanh ( z ) ) 2 z − tanh ( z ) z 2 {\displaystyle {\frac {1-\left(\tanh \left(z\right)\right)^{2}}{z}}-{\frac {\tanh \left(z\right)}{{z}^{2}}}} 微商實部 − R e ( − 1 − ( tanh ( x + i y ) ) 2 x + i y + tanh ( x + i y ) ( x + i y ) 2 ) {\displaystyle -{\it {Re}}\left(-{\frac {1-\left(\tanh \left(x+iy\right)\right)^{2}}{x+iy}}+{\frac {\tanh \left(x+iy\right)}{\left(x+iy\right)^{2}}}\right)} 微商虛部 − I m ( − 1 − ( tanh ( x + i y ) ) 2 x + i y + tanh ( x + i y ) ( x + i y ) 2 ) {\displaystyle -{\it {Im}}\left(-{\frac {1-\left(\tanh \left(x+iy\right)\right)^{2}}{x+iy}}+{\frac {\tanh \left(x+iy\right)}{\left(x+iy\right)^{2}}}\right)} 微商絕對值 | − 1 − ( tanh ( x + i y ) ) 2 x + i y + tanh ( x + i y ) ( x + i y ) 2 | {\displaystyle \left|-{\frac {1-\left(\tanh \left(x+iy\right)\right)^{2}}{x+iy}}+{\frac {\tanh \left(x+iy\right)}{\left(x+iy\right)^{2}}}\right|} 積分函數 ∫ 0 z tanh ( x ) x d x {\displaystyle \int _{0}^{z}\!{\frac {\tanh \left(x\right)}{x}}{dx}} 用其他特殊函數表示 t a n h c ( z ) = 2 K u m m e r M ( 1 , 2 , 2 z ) ( 2 i z + π ) K u m m e r M ( 1 , 2 , i π − 2 z ) e 2 z − 1 / 2 i π {\displaystyle tanhc(z)=2\,{\frac {{\rm {KummerM}}\left(1,\,2,\,2\,z\right)}{\left(2\,iz+\pi \right){{\rm {KummerM}}\left(1,\,2,\,i\pi -2\,z\right)}{{\rm {e}}^{2\,z-1/2\,i\pi }}}}} t a n h c ( z ) = 2 H e u n B ( 2 , 0 , 0 , 0 , 2 z ) ( 2 i z + π ) H e u n B ( 2 , 0 , 0 , 0 , 2 1 / 2 i π − z ) e 2 z − 1 / 2 i π {\displaystyle tanhc(z)=2\,{\frac {{\it {HeunB}}\left(2,0,0,0,{\sqrt {2}}{\sqrt {z}}\right)}{\left(2\,iz+\pi \right){\it {HeunB}}\left(2,0,0,0,{\sqrt {2}}{\sqrt {1/2\,i\pi -z}}\right){{\rm {e}}^{2\,z-1/2\,i\pi }}}}} t a n h c ( z ) = i W h i t t a k e r M ( 0 , 1 / 2 , 2 z ) W h i t t a k e r M ( 0 , 1 / 2 , i π − 2 z ) z {\displaystyle tanhc(z)={\frac {i{{\rm {\ WhittakerM}}\left(0,\,1/2,\,2\,z\right)}}{{{\rm {WhittakerM}}\left(0,\,1/2,\,i\pi -2\,z\right)}z}}} t a n h c ( z ) = i ( e 2 z − 1 ) ( e i π − 2 z − 1 ) e 2 z − 1 / 2 i π z {\displaystyle tanhc(z)={\frac {i\left({{\rm {e}}^{2\,z}}-1\right)}{\left({{\rm {e}}^{i\pi -2\,z}}-1\right){{\rm {e}}^{2\,z-1/2\,i\pi }}z}}} 級數展開 t a n h c ≈ ( 1 − 1 3 z 2 + 2 15 z 4 − 17 315 z 6 + 62 2835 z 8 − 1382 155925 z 10 + 21844 6081075 z 12 − 929569 638512875 z 14 + O ( z 16 ) ) {\displaystyle tanhc\approx (1-{\frac {1}{3}}{z}^{2}+{\frac {2}{15}}{z}^{4}-{\frac {17}{315}}{z}^{6}+{\frac {62}{2835}}{z}^{8}-{\frac {1382}{155925}}{z}^{10}+{\frac {21844}{6081075}}{z}^{12}-{\frac {929569}{638512875}}{z}^{14}+O\left({z}^{16}\right))} ∫ 0 z tanh ( x ) x d x = ( z − 1 9 z 3 + 2 75 z 5 − 17 2205 z 7 + 62 25515 z 9 − 1382 1715175 z 11 + O ( z 13 ) ) {\displaystyle \int _{0}^{z}\!{\frac {\tanh \left(x\right)}{x}}{dx}=(z-{\frac {1}{9}}{z}^{3}+{\frac {2}{75}}{z}^{5}-{\frac {17}{2205}}{z}^{7}+{\frac {62}{25515}}{z}^{9}-{\frac {1382}{1715175}}{z}^{11}+O\left({z}^{13}\right))} 圖像 Tanhc abs complex 3D Tanhc Im complex 3D plot Tanhc Re complex 3D plot Tanhc'(z) Im complex 3D plot Tanhc'(z) Re complex 3D plot Tanhc'(z) abs complex 3D plot Tanhc abs plot Tanhc Im plot Tanhc Re plot Tanhc'(z) Im plot Tanhc'(z) abs plot Tanhc'(z) Re plot Tanhc integral abs 3D plot Tanhc integral Im 3D plot Tanhc integral Re 3D plot Tanhc integral abs density plot Tanhc integral Im density plot Tanhc integral Re density plot 參看 Sinhc 函數 Coshc 函數 Tanc 函數 雙曲正弦積分函數 參考資料Loading content...Loading related searches...Wikiwand - on Seamless Wikipedia browsing. On steroids.