基本超几何函数是广义超几何函数的q模拟。 第一类基本超几何函数 j ϕ k [ a 1 a 2 … a j b 1 b 2 … b k ; q , z ] = ∑ n = 0 ∞ ( a 1 , a 2 , … , a j ; q ) n ( b 1 , b 2 , … , b k , q ; q ) n ( ( − 1 ) n q ( n 2 ) ) 1 + k − j z n {\displaystyle \;_{j}\phi _{k}\left[{\begin{matrix}a_{1}&a_{2}&\ldots &a_{j}\\b_{1}&b_{2}&\ldots &b_{k}\end{matrix}};q,z\right]=\sum _{n=0}^{\infty }{\frac {(a_{1},a_{2},\ldots ,a_{j};q)_{n}}{(b_{1},b_{2},\ldots ,b_{k},q;q)_{n}}}\left((-1)^{n}q^{n \choose 2}\right)^{1+k-j}z^{n}} 其中 ( a 1 , a 2 , … , a m ; q ) n = ( a 1 ; q ) n ( a 2 ; q ) n … ( a m ; q ) n {\displaystyle (a_{1},a_{2},\ldots ,a_{m};q)_{n}=(a_{1};q)_{n}(a_{2};q)_{n}\ldots (a_{m};q)_{n}} 其中 ( a ; q ) n = ∏ k = 0 n − 1 ( 1 − a q k ) = ( 1 − a ) ( 1 − a q ) ( 1 − a q 2 ) ⋯ ( 1 − a q n − 1 ) . {\displaystyle (a;q)_{n}=\prod _{k=0}^{n-1}(1-aq^{k})=(1-a)(1-aq)(1-aq^{2})\cdots (1-aq^{n-1}).} . 第二类基本超几何函数 j ψ k [ a 1 a 2 … a j b 1 b 2 … b k ; q , z ] = ∑ n = − ∞ ∞ ( a 1 , a 2 , … , a j ; q ) n ( b 1 , b 2 , … , b k ; q ) n ( ( − 1 ) n q ( n 2 ) ) k − j z n . {\displaystyle \;_{j}\psi _{k}\left[{\begin{matrix}a_{1}&a_{2}&\ldots &a_{j}\\b_{1}&b_{2}&\ldots &b_{k}\end{matrix}};q,z\right]=\sum _{n=-\infty }^{\infty }{\frac {(a_{1},a_{2},\ldots ,a_{j};q)_{n}}{(b_{1},b_{2},\ldots ,b_{k};q)_{n}}}\left((-1)^{n}q^{n \choose 2}\right)^{k-j}z^{n}.} 关系式 下列基本超几何函数在q->1时,化为超几何函数[1] lim q → 1 j ϕ k [ q a 1 q a 2 … q a j q b 1 q b 2 … q b k ; q , ( q − 1 ) ∗ z ] {\displaystyle \lim _{q\to 1}\;_{j}\phi _{k}\left[{\begin{matrix}q^{a_{1}}&q^{a_{2}}&\ldots &q^{a_{j}}\\q^{b_{1}}&q^{b_{2}}&\ldots &q^{b_{k}}\end{matrix}};q,(q-1)*z\right]} = j F k [ a 1 a 2 … a j b 1 b 2 … b k ; q , z ] {\displaystyle \;_{j}F_{k}\left[{\begin{matrix}a_{1}&a_{2}&\ldots &a_{j}\\b_{1}&b_{2}&\ldots &b_{k}\end{matrix}};q,z\right]} q二项式定理 下列公式是二项式定理的q模拟: 1 Φ 0 ( [ a ] , [ ] ; q ; z ) = {\displaystyle _{1}\Phi _{0}([a],[];q;z)=} ∑ n = 0 ∞ {\displaystyle \sum _{n=0}^{\infty }} ( a ; q ) n ( q ; q ) n {\displaystyle {\frac {(a;q)_{n}}{(q;q)_{n}}}} 参考文献Loading content...Loading related searches...Wikiwand - on Seamless Wikipedia browsing. On steroids.