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Lista de los campeones del Abierto de Australia de 1958:
Ashley Cooper (AUS) d. Malcolm Anderson (AUS), 7–5, 6–3, 6–4
Angela Mortimer Barrett (GBR) d. Lorraine Coghlan Robinson (AUS), 6–3, 6–4
Ashley Cooper/Neale Fraser (AUS)
Mary Bevis Hawton (AUS)/Thelma Coyne Long (AUS)
Mary Bevis Hawton (AUS)/Bob Howe (AUS)
| Predecesor: 1957 |
Abierto de Australia 1958 |
Sucesor: 1959 |
| Predecesor: Campeonato nacional de Estados Unidos 1957 |
Grand Slam 1958 |
Sucesor: Torneo de Roland Garros 1958 |
Datos: Q550332
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