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Germanium(IV) iodide
Chemical compound From Wikipedia, the free encyclopedia
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Germanium(IV) iodide is an inorganic compound with the chemical formula GeI4.
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Preparation
Germanium(IV) iodide can be obtained by the reaction of germanium and iodine[2] or the reaction of germanium dioxide and 57% hydriodic acid:[1]
- GeO2 + 4 HI → GeI4 + 2 H2O
Chemical properties
Germanium(IV) iodide reacts with tetraalkyl tin at 250 °C to form R2SnI2 and R2GeI2 (R= Et, Bu, Ph).[5] It reacts with germanium and sulfur at high temperatures to produce red GeSI2 and orange Ge2S3I2.[6] It reacts with diiron nonacarbonyl in an ionic liquid ([BMIm]Cl/AlCl3) at 130 °C to obtain Ge12[Fe(CO)3]8I4.[7]
- 12 GeI4 + 15 Fe2(CO)9 → Ge12[Fe(CO)3]8I4 + 22 FeI2 + 111 CO↑
Physical properties
Germanium(IV) iodide is an orange-red crystalline solid that hydrolyzes in water. It is soluble in carbon disulfide and benzene, but less soluble in carbon tetrachloride and chloroform.[3] It begins to decompose into germanium(II) iodide and iodine above its melting point.[8] Germanium(IV) iodide crystallizes in the cubic crystal system, space group Pa3 (space group no. 205), with the lattice parameter a = 11.89 Å. The crystal structure consists of tetrahedral GeI4 molecules.
References
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