Frobenius theorem (real division algebras)
Theorem in abstract algebra From Wikipedia, the free encyclopedia
Theorem in abstract algebra From Wikipedia, the free encyclopedia
In mathematics, more specifically in abstract algebra, the Frobenius theorem, proved by Ferdinand Georg Frobenius in 1877, characterizes the finite-dimensional associative division algebras over the real numbers. According to the theorem, every such algebra is isomorphic to one of the following:
These algebras have real dimension 1, 2, and 4, respectively. Of these three algebras, R and C are commutative, but H is not.
The main ingredients for the following proof are the Cayley–Hamilton theorem and the fundamental theorem of algebra.
The key to the argument is the following
Proof of Claim: Pick a in D with characteristic polynomial p(x). By the fundamental theorem of algebra, we can write
We can rewrite p(x) in terms of the polynomials Q(z; x):
Since zj ∈ C ∖ R, the polynomials Q(zj; x) are all irreducible over R. By the Cayley–Hamilton theorem, p(a) = 0 and because D is a division algebra, it follows that either a − ti = 0 for some i or that Q(zj; a) = 0 for some j. The first case implies that a is real. In the second case, it follows that Q(zj; x) is the minimal polynomial of a. Because p(x) has the same complex roots as the minimal polynomial and because it is real it follows that
for some k. Since p(x) is the characteristic polynomial of a the coefficient of x 2k − 1 in p(x) is tr(a) up to a sign. Therefore, we read from the above equation we have: tr(a) = 0 if and only if Re(zj) = 0, in other words tr(a) = 0 if and only if a2 = −|zj|2 < 0.
So V is the subset of all a with tr(a) = 0. In particular, it is a vector subspace. The rank–nullity theorem then implies that V has dimension n − 1 since it is the kernel of . Since R and V are disjoint (i.e. they satisfy ), and their dimensions sum to n, we have that D = R ⊕ V.
For a, b in V define B(a, b) = (−ab − ba)/2. Because of the identity (a + b)2 − a2 − b2 = ab + ba, it follows that B(a, b) is real. Furthermore, since a2 ≤ 0, we have: B(a, a) > 0 for a ≠ 0. Thus B is a positive-definite symmetric bilinear form, in other words, an inner product on V.
Let W be a subspace of V that generates D as an algebra and which is minimal with respect to this property. Let e1, ..., ek be an orthonormal basis of W with respect to B. Then orthonormality implies that:
The form of D then depends on k:
If k = 0, then D is isomorphic to R.
If k = 1, then D is generated by 1 and e1 subject to the relation e2
1 = −1. Hence it is isomorphic to C.
If k = 2, it has been shown above that D is generated by 1, e1, e2 subject to the relations
These are precisely the relations for H.
If k > 2, then D cannot be a division algebra. Assume that k > 2. Define u = e1e2ek and consider u2=(e1e2ek)*(e1e2ek). By rearranging the elements of this expression and applying the orthonormality relations among the basis elements we find that u2 = 1. If D were a division algebra, 0 = u2 − 1 = (u − 1)(u + 1) implies u = ±1, which in turn means: ek = ∓e1e2 and so e1, ..., ek−1 generate D. This contradicts the minimality of W.
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