2018 Australian Open – Wheelchair women's singles
2018 tennis event results From Wikipedia, the free encyclopedia
Diede de Groot defeated the defending champion Yui Kamiji in the final, 7–6(8–6), 6–4 to win the women's singles wheelchair tennis title at the 2018 Australian Open.
| Wheelchair women's singles | |
|---|---|
| 2018 Australian Open | |
| Champion | Diede de Groot |
| Runner-up | Yui Kamiji |
| Score | 7–6(8–6), 6–4 |
Seeds
Yui Kamiji (final)
Diede de Groot (champion)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
| First round | Semifinals | Final | ||||||||||||||||||
| 1 |  Yui Kamiji
| 6 | 7 | |||||||||||||||||
 Marjolein Buis
| 3 | 5 | ||||||||||||||||||
| 1 | Yui Kamiji
| 6 | 6 | |||||||||||||||||
 Sabine Ellerbrock
| 3 | 2 | ||||||||||||||||||
 Lucy Shuker
| 6 | 66 | 64 | |||||||||||||||||
| Sabine Ellerbrock
| 2 | 78 | 77 | |||||||||||||||||
| 1 | Yui Kamiji
| 66 | 4 | |||||||||||||||||
| 2 | Diede de Groot
| 78 | 6 | |||||||||||||||||
 Kgothatso Montjane
| 4 | 3 | ||||||||||||||||||
| Aniek van Koot
| 6 | 6 | ||||||||||||||||||
| Aniek van Koot
| 2 | 3 | ||||||||||||||||||
| 2 | Diede de Groot
| 6 | 6 | |||||||||||||||||
| WC | Katharina Krüger
| 1 | 1 | |||||||||||||||||
| 2 | Diede de Groot
| 6 | 6 | |||||||||||||||||
References
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