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1956 U.S. National Championships – Women's singles

1956 tennis event results From Wikipedia, the free encyclopedia

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First-seeded Shirley Fry defeated Althea Gibson 6–3, 6–4 in the final to win the women's singles tennis title at the 1956 U.S. National Championships.[2][3]

Quick Facts Women's singles, Final ...
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Seeds

The seeded players are listed below. Shirley Fry is the champion; others show in brackets the round in which they were eliminated.

  1. United States Shirley Fry (champion)
  2. United States Althea Gibson (finalist)
  3. United States Louise Brough (quarterfinals)
  4. United States Dorothy Knode (quarterfinals)
  5. United States Margaret duPont (quarterfinals)
  6. United Kingdom Shirley Bloomer (semifinals)
  7. United States Betty Pratt (semifinals)
  8. United States Darlene Hard (quarterfinals)

Draw

Key

Final eight

Quarterfinals Semifinals Finals
               
1 United States Shirley Fry 6 4 6
5 United States Margaret duPont 2 6 3
1 United States Shirley Fry 6 6
6 United Kingdom Shirley Bloomer 4 4
6 United Kingdom Shirley Bloomer 6 6
3 United States Louise Brough 3 3
1 United States Shirley Fry 6 6
2 United States Althea Gibson 3 4
4 United States Dorothy Knode 6 0 2
7 United States Betty Pratt 4 6 6
8 United States Betty Pratt 1 8
2 United States Althea Gibson 6 10
8 United States Darlene Hard 7 1
2 United States Althea Gibson 9 6
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References

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