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1956 U.S. National Championships – Women's singles
1956 tennis event results From Wikipedia, the free encyclopedia
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First-seeded Shirley Fry defeated Althea Gibson 6–3, 6–4 in the final to win the women's singles tennis title at the 1956 U.S. National Championships.[2][3]
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Seeds
The seeded players are listed below. Shirley Fry is the champion; others show in brackets the round in which they were eliminated.
Shirley Fry (champion)
Althea Gibson (finalist)
Louise Brough (quarterfinals)
Dorothy Knode (quarterfinals)
Margaret duPont (quarterfinals)
Shirley Bloomer (semifinals)
Betty Pratt (semifinals)
Darlene Hard (quarterfinals)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- r = Retired
Final eight
Quarterfinals | Semifinals | Finals | ||||||||||||||||||
1 | ![]() | 6 | 4 | 6 | ||||||||||||||||
5 | ![]() | 2 | 6 | 3 | ||||||||||||||||
1 | ![]() | 6 | 6 | |||||||||||||||||
6 | ![]() | 4 | 4 | |||||||||||||||||
6 | ![]() | 6 | 6 | |||||||||||||||||
3 | ![]() | 3 | 3 | |||||||||||||||||
1 | ![]() | 6 | 6 | |||||||||||||||||
2 | ![]() | 3 | 4 | |||||||||||||||||
4 | ![]() | 6 | 0 | 2 | ||||||||||||||||
7 | ![]() | 4 | 6 | 6 | ||||||||||||||||
8 | ![]() | 1 | 8 | |||||||||||||||||
2 | ![]() | 6 | 10 | |||||||||||||||||
8 | ![]() | 7 | 1 | |||||||||||||||||
2 | ![]() | 9 | 6 |
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References
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