Ramapo, New York
Town in New York, United States / From Wikipedia, the free encyclopedia
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Ramapo is a town in Rockland County, New York, United States. It was originally formed as New Hampstead, in 1791, and became Ramapo in 1828.[2] It shares its name with the Ramapo River. As of the 2020 census, Ramapo had a total population of 148,919, making it the most populous town in New York outside of Long Island. If all towns in New York were cities, Ramapo would be the 12th-largest city in the state of New York.
This article needs additional citations for verification. (October 2014) |
Ramapo, New York | |
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Downtown Suffern, a village in Ramapo | |
![]() Location in Rockland County and the state of New York. | |
Coordinates: 41°7′19″N 74°5′0″W | |
Country | United States |
State | New York |
County | Rockland |
Government | |
• Supervisor | Michael Specht (D) |
Area | |
• Total | 61.84 sq mi (160.16 km2) |
• Land | 61.14 sq mi (158.35 km2) |
• Water | 0.70 sq mi (1.80 km2) |
Elevation | 371 ft (113 m) |
Population (2020) | |
• Total | 148,919 |
• Density | 2,400/sq mi (930/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 10901, 10952, 10977, 10970, 10965, 10974 |
Area code | 845 |
FIPS code | 36-60510 |
GNIS ID | 0979406 |
Website | ramapo.org |
The town's name, recorded variously as Ramopuck, Ramapock, or Ramapough, is of Lenape origin, meaning either "sweet water" or "slanting rocks". Early maps referred to Ramapo as Ramepog (1695), Ramepogh (1711), and Ramapog (1775).[3]
The town is located south of Haverstraw and west of Clarkstown and Orangetown.