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Chemical compound From Wikipedia, the free encyclopedia
Samarium(III) bromide is a crystalline compound of one samarium and three bromine atoms with the chemical formula of SmBr3. Samarium(III) bromide is a dark brown powder at room temperature.[4] The compound has a crystal structure isotypic to that of plutonium(III) bromide.[5][6]
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Names | |
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IUPAC name
samarium(III) bromide | |
Other names
samarium tribromide tribromosamarium | |
Identifiers | |
3D model (JSmol) |
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ChemSpider | |
ECHA InfoCard | 100.033.938 |
EC Number |
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PubChem CID |
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CompTox Dashboard (EPA) |
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Properties | |
SmBr3 | |
Molar mass | 390.07 g·mol−1 |
Appearance | Light yellow solid[1][2] |
Melting point | 700 °C (1,292 °F; 973 K)<[3] |
+972.0·10−6 cm3/mol | |
Hazards | |
GHS labelling: | |
Warning | |
H315, H319, H335[3] | |
P261, P305+P351+P338[3] | |
Related compounds | |
Other anions |
Samarium(III) fluoride Samarium(III) chloride |
Other cations |
Samarium(II) bromide |
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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SmBr3·6H2O can be crystallized by dissolving samarium oxide in 40% hydrobromic acid. The hydrate and ammonium bromide are heated in a vacuum to obtain the anhydrous form of samarium(III) bromide.[2]
Samarium(III) bromide forms some compounds with hydrazine, such as SmBr3·3N2H4·H2O which is a pale yellow needle-shaped crystal that is soluble in water and ethanol but insoluble in benzene, with d20 °C = 3.147 g/cm3.[7]
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