Iridium(IV) iodide is a binary chemical compound of iridium and iodide with the chemical formula IrI
4
.[1][2][3]

Quick Facts Names, Identifiers ...
Iridium(IV) iodide
Names
Other names
Iridium(IV) iodide, tetraiodoiridium
Identifiers
3D model (JSmol)
ChemSpider
ECHA InfoCard 100.029.279 Edit this at Wikidata
EC Number
  • 232-206-3
  • InChI=1S/4HI.Ir/h4*1H;/q;;;;+4/p-4
    Key: BUUWLOZTIYBNKB-UHFFFAOYSA-J
  • I[Ir](I)(I)I
Properties
I4Ir
Molar mass 699.835 g·mol−1
Appearance Black powder
Melting point 100 °C (212 °F; 373 K)
insoluble
Structure
hexagonal
Related compounds
Related compounds
Iridium triiodide, platinum tetraiodide
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).
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Preparation

Iridium(IV) iodide can be obtained by reacting dipotassium hexachloroiridate or hexachloroiridic acid with an aqueous solution of potassium iodide.[4][5]

Properties

Iridium tetraiodide forms black crystals, does not dissolve in water and alcohol.[6][7][8] In alkali metal iodide solutions, the compound dissolves easily to give a ruby red solution, forming complex salts.[5]

The compound decomposes when heated:[citation needed]

IrI4 → Ir + 2I2

Uses

Iridium(IV) iodide can be used as a catalyst in organic chemistry.[9][8]

References

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