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Gainesville, New York
Town in New York, United States / From Wikipedia, the free encyclopedia
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Gainesville is an incorporated town in Wyoming County, New York. The population was 2,333 at the 2000 census. The town is named after General Edmund P. Gaines.
For the village within the town, see Gainesville (village), New York.
Quick Facts Country, State ...
Gainesville | |
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![]() The ice age left rolling, but fertile land | |
![]() Location within Wyoming County and New York | |
Coordinates: 42.641°N 78.134°W / 42.641; -78.134 | |
Country | United States |
State | New York |
County | Wyoming |
Area | |
• Total | 35.71 sq mi (92.48 km2) |
• Land | 35.57 sq mi (92.13 km2) |
• Water | 0.14 sq mi (0.36 km2) |
Elevation | 1,660 ft (510 m) |
Population (2010) | |
• Total | 2,182 |
• Estimate (2016)[3] | 2,118 |
• Density | 59.54/sq mi (22.99/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
FIPS code | 36-27980 |
GNIS feature ID | 978982 |
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The Town of Gainesville is on the eastern border of the county. Gainesville is also the name of a village in the town.