Coxsackie, New York
Town in New York, United States / From Wikipedia, the free encyclopedia
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For the village located within this town, see Coxsackie (village), New York.
Coxsackie (/kʊkˈsæki/ kuuk-SAK-ee[3]) is a town in Greene County, New York, United States. The population in the 2020 census was 8,382, a decrease from the 2010 census.[2] It is the second-largest town in Greene County after Catskill. The name of the town is said to be derived from a Native American term, but it has various translations ("owl's hoot" is locally common).[4]
Quick Facts Country, State ...
Coxsackie, New York | |
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Coordinates: 42°21′27″N 73°48′29″W | |
Country | United States |
State | New York |
County | Greene |
Government | |
• Town Supervisor | Richard K. Hanse |
• Town Council | |
Area | |
• Total | 2.59 sq mi (6.72 km2) |
• Land | 2.17 sq mi (5.62 km2) |
• Water | 0.42 sq mi (1.10 km2) |
Population | |
• Total | 8,382 |
• Density | 3,200/sq mi (1,200/km2) |
Time zone | UTC-5 (EST) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 12051 |
Area code | 518 |
FIPS code | 36-039-18729 |
Website | coxsackie |
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Within the area governed as a town, there is also a village called Coxsackie. The town is in the northeastern part of the county.
The town of Coxsackie is notable for being the namesake of the Coxsackievirus (a type of enterovirus), which was first isolated in this town.