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Bloomingdale, Indiana
Town in Indiana, United States / From Wikipedia, the free encyclopedia
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Bloomingdale is a town in Penn Township, Parke County, in the U.S. state of Indiana.[2] The population was 335 at the 2010 census.
Quick Facts Country, State ...
Bloomingdale, Indiana | |
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![]() | |
![]() Location of Bloomingdale in Parke County, Indiana. | |
Coordinates: 39°49′50″N 87°14′57″W | |
Country | ![]() |
State | ![]() |
County | Parke |
Township | Penn |
Area | |
• Total | 0.58 sq mi (1.51 km2) |
• Land | 0.58 sq mi (1.51 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 646 ft (197 m) |
Population (2020) | |
• Total | 269 |
• Density | 462.20/sq mi (178.59/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-5 (EST) |
ZIP code | 47832 |
Area code | 765 |
FIPS code | 18-05788 |
GNIS ID | 2396593[2] |
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