1992 United States presidential election in Iowa
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The 1992 United States presidential election in Iowa took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.
Main article: 1992 United States presidential election
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Iowa was won by Democratic Governor Bill Clinton of Arkansas with 43.29% of the popular vote over incumbent Republican President George H. W. Bush's 37.27%, a victory margin of 6.01%. Independent businessman Ross Perot finished in third, with 18.71% of the popular vote.[1] Clinton ultimately won the national vote, defeating incumbent President Bush and Perot.[2] Iowa was the only state which swung more Republican than it had been in 1988.