1946 Wimbledon Championships – Women's singles
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Pauline Betz defeated Louise Brough in the final, 6–2, 6–4 to win the ladies' singles tennis title at the 1946 Wimbledon Championships.[1] Alice Marble was the defending champion, but was ineligible to compete after turning professional.
Quick Facts Women's singles, Final ...
Women's singles | |||||||||||||
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1946 Wimbledon Championships | |||||||||||||
Final | |||||||||||||
Champion | ![]() | ||||||||||||
Runner-up | ![]() | ||||||||||||
Score | 6–2, 6–4 | ||||||||||||
Details | |||||||||||||
Draw | 96 | ||||||||||||
Seeds | 8 | ||||||||||||
Events | |||||||||||||
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Main article: 1946 Wimbledon Championships