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The 1832 United States presidential election in Delaware took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
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County Results
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Delaware voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won the state by a narrow margin of 1.98%. This was the first election in which Delaware voted by popular vote for president in a contested election. It had used the congressional district method in the uncontested election of 1788–89, but had since changed to selecting its electors through the state legislature from 1792 to 1828.[1]
1832 United States presidential election in Delaware[2] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
National Republican | Henry Clay | 4,276 | 50.99% | 3 | |
Democratic | Andrew Jackson (inc.) | 4,110 | 49.01% | 0 | |
Totals | 8,386 | 100.00% | 3 | ||
County | Henry Clay
National Republican |
Andrew Jackson
Democratic |
Margin | Total votes cast | |||
# | % | # | % | # | % | ||
Kent | 1,167 | 53.56% | 1,012 | 46.44% | 155 | 7.11% | 2,179 |
New Castle | 1,335 | 43.77% | 1,715 | 56.23% | −380 | −12.46% | 3,050 |
Sussex | 1,774 | 56.19% | 1,383 | 43.81% | 391 | 12.39% | 3,157 |
Total: | 4,276 | 50.99% | 4,110 | 49.01% | 166 | 1.98% | 8,386 |
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