Shelby Township, Jefferson County, Indiana
Township in Indiana, United States / From Wikipedia, the free encyclopedia
Shelby Township is one of ten townships in Jefferson County, Indiana, United States. As of the 2020 census, its population was 1,151 and it contained 458 housing units.[1]
More information Census, Pop. ...
Census | Pop. | Note | %± |
---|---|---|---|
1890 | 1,583 | — | |
1900 | 1,441 | −9.0% | |
1910 | 1,330 | −7.7% | |
1920 | 1,271 | −4.4% | |
1930 | 1,091 | −14.2% | |
1940 | 1,041 | −4.6% | |
1950 | 978 | −6.1% | |
1960 | 822 | −16.0% | |
1970 | 705 | −14.2% | |
1980 | 850 | 20.6% | |
1990 | 827 | −2.7% | |
2000 | 1,052 | 27.2% | |
2010 | 1,133 | 7.7% | |
2020 | 1,151 | 1.6% | |
Source: US Decennial Census[2] |
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Quick Facts Country, State ...
Shelby Township | |
---|---|
Coordinates: 38°52′43″N 85°16′34″W | |
Country | United States |
State | Indiana |
County | Jefferson |
Government | |
• Type | Indiana township |
Area | |
• Total | 48.51 sq mi (125.6 km2) |
• Land | 48.33 sq mi (125.2 km2) |
• Water | 0.18 sq mi (0.5 km2) 0.37% |
Elevation | 823 ft (251 m) |
Population (2020) | |
• Total | 1,151 |
• Density | 24/sq mi (9.2/km2) |
GNIS feature ID | 0453844 |
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